18x^2-30x-50=0

Solution for 18x^2-30x-50=0 equation:

18x^2-30x-50=0

a = 18; b = -30; c = -50;
Δ = b2-4ac
Δ = -302-4·18·(-50)
Δ = 4500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4500}=\sqrt{900*5}=\sqrt{900}*\sqrt{5}=30\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30\sqrt{5}}{2*18}=\frac{30-30\sqrt{5}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30\sqrt{5}}{2*18}=\frac{30+30\sqrt{5}}{36}
$